A rectangle has sides #x^2 + 4x# and #4x+12#, what is its area?

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Answer 1 · 2017-11-20T06:46:17

The area of the rectangle is #4x^3+28x^2+48x# units squared.

A rectangle's area is calculated by using the formula: #A=lw#. Other variants include #A=bh#.

#A=lw#

#=(x^2+4x)(4x+12)#

At this point, we are now going to foil the equation. This is how you multiply two binomials.

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#=4x^3+12x^2+16x^2+48x#

Now we simplify.

#=4x^3+28x^2+48x#

Therefore, the area of the rectangle is #4x^3+28x^2+48x# units squared.

Hope this helps :)