Question

How do you factor `8y ^ { 3} x - 10y ^ { 2} x - 32y ^ { 3} + 40y ^ { 2}`?

Answer 1

`2y^2(x-4)(4y-5)`

Explanation:

`8y^3x-10y^2x-32y^3+40y^2`
`=> 2xy^2(4y-5)-8y^2(4y-5)`
`=> (2xy^2-8y^2)(4y-5)`
`=> 2y^2(x-4)(4y-5)`