How do you factor 8y ^ { 3} x - 10y ^ { 2} x - 32y ^ { 3} + 40y ^ { 2}?

1 Answer
Nov 20, 2017

2y^2(x-4)(4y-5)

Explanation:

8y^3x-10y^2x-32y^3+40y^2
=> 2xy^2(4y-5)-8y^2(4y-5)
=> (2xy^2-8y^2)(4y-5)
=> 2y^2(x-4)(4y-5)