Question #77aa9

1 Answer
Nov 21, 2017

See Below.

Explanation:

We will use the equation #q=s*m*DeltaT# where #q# is heat, #s# is the specific heat, #m# is the mass, and #DeltaT# is the change in temperature. So far, we can plug in these numbers:

#1,921=s*22.32*110.2#, which we can simplify to:

#1,921=s*2,459#

Now, we can solve for #s# algebraically by dividing by 2,459 on both sides:

#0.7812=s#

The units of specific heat capacity are in #"J"/("gram"*C)#

I hope this helps!