Question #d259d
1 Answer
B
Explanation:
Understanding that displacement is equal to the area under a velocity graph, to find the answer to this particular question, just look at the graphs and see which one covers the most area of the rectangle you are looking at.
Analyzing each on their own:
1.
Graph one covers maybe a third of the area, and even has the particle go backwards for part of it, so we'll assume it's wrong.
2.
This graph covers most of the 1x1 rectangle, so it's a good candidate.
3.
This graph covers less than half, so graph 2 is looking better.
4.
This one looks like the particle, in total, experiences 0 displacement.
5.
This particle has the area under the graph be exactly half of the 1x1 rectangle, so 2 is still the best option.
And there you go.
2 covers the most area in the velocity vs time graph, therefore it has the most displacement.
