How do you solve # 4(2-x) > -2x-3(4x 1)#?

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Answer 1 · 2017-11-21T19:27:36

#x > -11/10#

I suppose you meant to write #4(2-x) > -2x - 3(4x + 1)#, and if we were to solve this, the first thing to do is distribute.

Usually, we solve inequalities just like equations, with a small change.

The '4' multiplies both the 2 and -x, so it becomes #8-4x#.
The '-3' multiplies both the 4x and 1, so it becomes #-12x - 3#.

When we put them back into the inequality, it becomes this:
#8 - 4x > -2x - 12x - 3#

Now we need to simplify.
#8 - 4x > -14x - 3#

#10x > -11#

#x > -11/10#