How to find for the missing parts in the following diagrams below?
1 Answer
Nov 22, 2017
Explanation:
#color(blue)"First diagram"#
#"we can solve using "color(blue)"trig. ratios"#
#tan60^@="opposite"/"adjacent"="long"/(5sqrt3)#
#rArr"long "=5sqrt3xxtan60^@=5sqrt3xxsqrt3=15#
#cos60^@="adjacent"/"hypotenuse"=(5sqrt3)/"hypotenuse"#
#rArr"hypotenuse "=(5sqrt3)/(cos60^@)=(5sqrt3)/(1/2)=10sqrt3#
#color(blue)"Second diagram"#
#sin30^@="opposite"/"hypotenuse"="short"/(6sqrt3)#
#rArr"short "=6sqrt3xxsin30^@=6sqrt3xx1/2=3sqrt3#
#cos30^@="long"/(6sqrt3)#
#rArr"long "=6sqrt3xxcos30^@=6sqrt3xxsqrt3/2=9#