Question

Compute the acceleration due to gravity at a place where a simple pendulum 150cm long makes 100 vibrations 245sec?

Answer 1

`"9.86 m/s"^2`

Explanation:

Time period`= "245 seconds"/"100 vibrations" = "2.45 seconds"`

Also, for simple pendulum

`T = 2pisqrt(l/g)`

Rearranging above equation we get

`g = (4pi^2l)/T^2 = (4 × (3.14)^2 × "1.50 m")/(("2.45 s")^2) = "9.86 m/s"^2`

How do you solve for `g` in `T = 2pisqrt(l/g)`?