How do you graph #-x+2y=1#?

Question

2486 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-23T05:32:58

Refer Explanation section

Given -

#-x+2y=1#

Find the y and x intercepts

Y- intercept
At #x=0; -(0)+2y=1#

#y=1/2#

#(0, 0.5)# is one of the points on the Line

X-intercept

At #y=0; -x+2(0)=1#

#-x=1#

#x=-1#

#(-1, 0) #is another point on the straight line.

Plot these two points and join them with a straight line.

enter image source here