Question

Question #9f025

Answer 1

No it is not..

Explanation:

`(a-b)^2=a^2-2ab+b^2`
`x^6-y^6=[(x-y)^2]^3`
`x^6-y^6=[x^2-2xy+y^2]^3`
Let, `x^2-2xy` be `a`
And, `y^2` be `b`
`(a+b)^3`
Which is clearly not equal to what you said