Question #fc046

1 Answer
Al E.
Nov 24, 2017

#PV = nRT#

#45.3mmHg * (atm)/(760mmHg) * 356mL * L/(10^3mL) = n * (0.08206L*atm)/(mol*K) * 309.7K#
#therefore n_(F_2) approx 8.35*10^-4mol#

As Ernest states, we'll need the mass to "calculate" the molar mass, even though you and I know it's really 38g/mol.

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