Question #08228

1 Answer
Nov 25, 2017

#lim_(x->-1) sqrt(x+1)= 0#

Explanation:

You can substitute #-1# for #x#.

#lim_(x->-1) sqrt(x+1) = sqrt(-1+1) = sqrt 0 = 0 #

graph{sqrt(x+1) [-10, 10, -5, 5]}

The graph above also shows that as you approach #x=-1#, the value of the function approaches #0#.