How do you solve #(x ^ { 3} + 5x ^ { 2} \cdot 6x - 2) \div ( x - 1)#?

1 Answer
Morgan S.
Nov 26, 2017

#31x^2+31x+31+\frac{29}{x-1}#

Explanation:

First, we can simplifying the terms of the dividend:

#(x^3+5x^2\cdot 6x-2)\div(x-1)#

#=(x^3+30x^3-2)\div(x-1)#

#=(31x^3-2)\div(x-1)#

Since the divisor is in the form #(x-c)#, we can use synthetic division:

enter image source here

Related questions
Impact of this question
852 views around the world
You can reuse this answer
Creative Commons License