How do you solve #x^ { 2} - 16x = 24#?

1 Answer
Manikandan S.
Nov 28, 2017

Convert to quadratic equation

Explanation:

#x^2-16x=24 #

#x^2-16x-24 = 0#

#x = (-b \pm sqrt(b^2-4ac))/(2a)#

#x = (16 \pm sqrt(256+96))/2#

#x = (\cancel(16)8 \pm \cancel(sqrt(16))2 sqrt(16+6))/\cancel(2)#

#x = 8 \pm 2 sqrt(22)#

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