Question

How do you simplify `\frac { 3} { 21x ^ { 2} } \cdot 24x ^ { 3}`?

Answer 1

`(24x)/7`

Explanation:

Given: `3/(21x^2)*24x^3`

We begin by cancelling the like terms, that is;
`cancel(3)/(cancel(21)cancel(x^2))*24cancel(x^3) = (color(red)(24)color(red)(x))/color(red)7`

Answer 2

`(24x)/7`

Explanation:

`3/(21x^2)xx(24x^3)/1`

`color(blue)"cancel common factors ""on numerator/denominator"`

`cancel(3)^1/(cancel(21)^7xx cancel(x)xxcancel(x))xx(24xx cancel(x)xxcancel(x)xx x)/1`

`=(24x)/7`