How do you evaluate #(2x ^ { 5} ) ( - 3x ^ { 9} ) ( 9x ^ { 9} )#?

2 Answers
Nov 29, 2017

you should be able to do it in your head - it's not difficult:

Explanation:

  1. Multiply the constants 2, -3, and 9. (-54)

  2. Multiply the powers of 'x' terms, by writing x, raised to a power equal to the SUM of the powers of the original terms.

This is #x^(5 + 9 + 9) = x^23#

  1. Put it all together:

#-54x^23#

GOOD LUCK

Nov 29, 2017

See a solution process below:

Explanation:

First, rewrite the expression as:

#(2 xx -3 xx 9)(x^5 xx x^9 xx x^9) =>#

#-54(x^5 xx x^9 xx x^9)#

Now, use this rule for exponents to multiply the #x# terms:

#x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))#

#-54(x^color(red)(5) xx x^color(blue)(9) xx x^color(green)(9)) =>#

#-54x^(color(red)(5)+color(blue)(9)+color(green)(9)) =>#

#-54x^23#