How do I find the #lim_(x to 6) (5x)/(3+x^8)#?
#lim_(x to 6) (5x)/(3+x^8)#
I'm confused, because the number it seems to approach is .00001786 when I plug 6 and numbers close to 6 inside. However, the website I have my math homework on says that it is incorrect. Undefined and 0 are also not accepted answers. Am I supposed to reduce this somehow? Or am I doing the order of operations wrong?
I'm confused, because the number it seems to approach is .00001786 when I plug 6 and numbers close to 6 inside. However, the website I have my math homework on says that it is incorrect. Undefined and 0 are also not accepted answers. Am I supposed to reduce this somehow? Or am I doing the order of operations wrong?
1 Answer
Nov 29, 2017
There is no discontinuity at the specified limit, therefore, the limit is is value at that point.
Explanation:
Given:
The limit is merely the expression evaluate at the specified value:
This is a number very near 0 but it is not 0; it is not a surprise that the website says that 0 is an unacceptable answer.