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Answer 1 · 2017-11-29T13:48:44

#"4.0 g"#

In water calcium exist as #"Ca"^(2+)# ions.

#"Normality" = "Equivalents of solute"/"Volume of solution (in litre)"#

From above formula

Equivalents of #"Ca"^(2+)# ions#= "0.2 N" × 250 cancel"ml" × (10^-3 "L")/cancel"ml" = "0.05 equivalents"#

#"Equivalents" = "Moles" / ("n-factor")#

#"n-factor"# of #"Ca"^(2+)# is #2#

Moles of #"Ca"^(2+)# ions#= 0.05 × 2 = "0.1 mol"#

Molar mass of calcium is #"40 g/mol"#

Mass of #"Ca"^(2+) = 0.1 cancel"mol" × "40.0 g"/cancel"mol" = underlinecolor(black) "4.0 g"#