How do you solve x^ { 2} - 4( \frac { 3- x } { 2} ) ^ { 2} = - 33?

1 Answer
Nov 29, 2017

Start by expanding the bracket completely, then simplify it and rearrange to solve.

Explanation:

The equation can be rewritten as this:
x^2-4(3-x)^2/(2)^2+33=0

Expand the brackets
x^2-4((9-6x+x^2)/4)+33=0

The 4s cancel out, which gives you:
x^2-(9-6x+x^2)+33=0

Expand and simplify:
x^2-9+6x-x^2+33=0
24+6x=0

Solve:
6x=-24
x=-24/6
x=-4