Question

How do you solve `x^ { 2} - 4( \frac { 3- x } { 2} ) ^ { 2} = - 33`?

Answer 1

Start by expanding the bracket completely, then simplify it and rearrange to solve.

Explanation:

The equation can be rewritten as this:
`x^2-4(3-x)^2/(2)^2+33=0`

Expand the brackets
`x^2-4((9-6x+x^2)/4)+33=0`

The 4s cancel out, which gives you:
`x^2-(9-6x+x^2)+33=0`

Expand and simplify:
`x^2-9+6x-x^2+33=0`
`24+6x=0`

Solve:
`6x=-24`
`x=-24/6`
`x=-4`