How do you write the first five terms of the sequence #a_n=n/(n+2)#?

1 Answer
turksvids
Nov 30, 2017

The first 5 terms are: #{1/3, 2/4, 3/5, 4/6, 5/7}#. (I didn't reduce so the pattern would be more clear.)

Explanation:

I'm assuming that we start at #n=1# for this.

Substitute #n=1# to get #a_1 = 1/3#.
Substitute #n=2# to get #a_2 = 2/4 = 1/2#.
Substitute #n=3# to get #a_3 = 3/5#.
Substitute #n=4# to get #a_4 = 4/6 = 2/3#.
Substitute #n=5# to get #a_5 = 5/7#.

So the first 5 terms are: #{1/3, 2/4, 3/5, 4/6, 5/7}#.

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