For the reaction Cl2(g) + KBr(s) to KCl(s) + Br2(g),how many grams of potassium chloride can be produced from 300 grams of potassium bromide? a.98.7g b.111g c.188g d.451g
1 Answer
See below.
Explanation:
Step 1: Balance the chemical equation.
Step 2: Identify the limiting reagent.
This is the compound that will basically run out first, but this problem doesn't give us the amount of
Step 3: Convert grams to moles using
Step 4: Find out how many moles of
It is important to note this ratio is NOT a mass ratio (i.e. 300g of
Step 5: Convert moles to grams using the molar mass of
Thus, c (188 g) will be the correct answer.
Hope this helps!