Question

How do you solve `23f ^ { 2} + 21f - 2= 0`?

Answer 1

`f_1=2/23 and f_2=-1`

Explanation:

By using the quadratic formula:

`x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`

In your case `a=23, b=21 and c=-2`

Plugging in these values one obtains:

`f_1=2/23 and f_2=-1`