How do you solve #-22+ \frac { x } { 3} = 4#?

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Answer 1 · 2017-12-01T04:55:52

#x=78#

I’m assuming you are solving for x

So you want to isolate x by itself.

Let’s start by adding both sides by 22 (what you do on the left, you must do on the right!)

#-22+x/3 = 4 #

#-22 + 22 +x/3 = 4 +22#

Notice that -22+22=0, so that cancels out and we get:

#x/3 = 26#

Now we would still want to get x by itself, so the next move is to multiply both sides by 3 to cancel out the denominator.

#x/3 = 26#

#x/3 *3 = 26 *3 #

#x = 78 #