How do you simplify \frac { 8+ 6i } { 3- 2i }?

1 Answer
Dec 2, 2017

(12+34i)/13

Explanation:

In order to simplify this, you need to make sure i isn't in the denominator (or bottom) of the fraction. To do this, multiply both the numerator and denominator by the conjugate of 3-2i, which is 3+2i. When doing this, make sure to use the FOIL method:

1)

((8+6i) * (3+2i))/((3-2i) * (3+2i))

2)

(24+16i+18i-12)/(9+6i-6i-4i^2)

Since i equals sqrt(-1), i^2 equals -1.

3)

(12+34i)/(9+4)

4)

(12+34i)/(13)