How do you solve this system of equations: #9y = 3x + 18 and 13x - y = - 2#?

1 Answer

the value of #x=0 and y=2#

Explanation:

the two given equations are #9y=3x+18-(1)#
#13x-y=-2->(2)# from #(2)rArry=13x+2->(3)#
put #(3)# in #(1)#
we get #9(13x+2)=3x+18rArr117x+18=3x+18rArr114x=0rArrx=0#
#:.x=0# put #x=0# in #(2)# we get #y=0+2rArry=2#
#:.# the value of #x=0 and y=2#