What molar quantity is contained in a #552*mL# volume of #"CCl"_4(g)# at #100# #""^@C#, and a pressure of #1.01*atm#?

1 Answer
anor277
Dec 2, 2017

We solve for #n# in the Ideal Gas equation....and get a mass of approx. #3*g#...

Explanation:

The normal boiling point of #"carbon tetrachloride"# is #76.7# #""^@C#, and thus we assume that the #"carbon tet"# is present in the gaseous phase (the pressure is #1.01*atm#)....

#n=(PV)/(RT)=(1.01*atmxx552*mLxx10^-3*L*mL^-1)/(0.0821*(L*atm)/(K*mol)xx373.1*K)#

#=0.0182*mol#

And we multiply this molar quantity by the molar mass of #"carbon tet"#, i.e. #0.0182*molxx153.82*g*mol^-1=??*g#

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