Question #802bb

2 Answers
Dec 3, 2017

9p^2 + 15p + 6

Explanation:

(3p+3)(3p+2)

  1. Multiply the 3p and the 3p for the first term
  2. Multiply the 3p and the 2 for the second term
  3. Multiply the 3 and the 3p for the third term
  4. Multiply the 3 and the 2 for the fourth term

This is what it should look like in the end:

9p^2 + 6p + 9p + 6

Notice how the second and third terms have the same variable of x
Add both of the numbers together so there will only by one number with the x variable. It should look like this in the end:

9p^2 + 15p + 6

Dec 3, 2017

you can use distributive property or this formula
(x+a)(x+b)=x^2+(a+b)x+ab
Distributive property is
(a+b)(c+d)=a(c+d)+b(c+d)=ac+ad+bc+bd
Here, a,b,c,d can be anything, they even can be the same number
So, using this
(3p)^2+(3+2)xx3p+3xx2
Notice that (3p)^2 != 3p^2
9p^2+5xx3p+6
Solve
9p^2+15p+6