How do you solve $- 4 x + 5 y = 6$ $-4x + 5y = 6$ and $3 x + y = - 14$ $3x + y = - 14$ ?

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Answer 1 · 2017-12-03T16:35:54

$y = - 2, x = - 4$ $y=-2 ,x =-4$

$:.-4x+5y=6$ -----(1)

$:.3x+y=-14$ ------(2)

$:.(1)xx3$

$:.-12x+15y=18$ ----(3)

$:.(2)xx4$

$:.12x+4y=-56$ ------(4)

$:.(3)+(4)$

$:.19y=-38$

$y=-38/19$

$:.y=-2$

substitute y=-2 in------(2)

$:.3x+(-2)=-14$

$:.3x-2=-14$

$:.3x=-14+2$

$:.3x=-12$

$:.x=-12/3$

$:.x=-4$

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check:-

substitute $y=-2$ and $x=-4$ in ----(1)

$:.-4(-4)+5(-2)=6$

$:.16-10=6$

$:.6=6$

How do you solve -4x + 5y = 6−4x+5y=6-4x + 5y = 6 and 3x + y = - 143x+y=−143x + y = - 14?