Question

Question #a621d

Answer 1

I am assuming missing parentheses to get `f(x) = axe^(bx^2)`. Which makes `b=-1/18` and `a = 7/3sqrte`

Explanation:

`f'(x) = ae^(bx^2)(1+2bx^2) = 0` at `x^2 = -1/(2b)`

So we need `x = sqrt(-1/(2b))=3` and so,

`b = -1/18`

Now we have `f(x) = axe^(-x^2/18)`.

We also want `f(x) = 7`, so solve

`a(3)(e^(-1/2)) = 7` for `a = 7/3e^(1/2)`