Question #523a5

1 Answer
yumean1119
Dec 4, 2017

#d=3002/5013#

Explanation:

First, "translate" the question into equation.

#12 3/10+5 13/1000d=15 302/1000#

To simplify this, multiple both sides by #1000#.
#12300+5013d=15302#

Substract #12300# from both sides.
#5013d=15302-12300#
#5013d=3002#

And you got the result. #d=3002/5013#.
This fraction cannot be reduced since 5013 and 3002 are coprime.
#5013=3^2*557#
#3002=2*19*79#
→#gcd(5013,3002)=1#.

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