First, subtract #color(red)(10)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:
#28 - color(red)(10) > 10 - color(red)(10) - 9x#
#18 > 0 - 9x#
#18 > -9x#
Now, divide each side of the inequality by #color(blue)(-9)# to solve for #x# while keeping the inequality balanced. However, because we are multiplying or dividing and inequality by a negative number we must reverse the inequality operator:
#18/color(blue)(-9) color(red)(<) (-9x)/color(blue)(-9)#
#-2 color(red)(<) (color(red)(cancel(color(black)(-9)))x)/cancel(color(blue)(-9))#
#-2 < x#
To state the solution in terms of #x# we can reverse or "flip" the entire inequality:
#x > -2#
