How do you solve #(4x + 1) ( 2x - 2) \geq 8x ( x + 5)#?

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Answer 1 · 2017-12-04T08:57:10

#x<=-1/23#

First we expand out the brackets:

#(4x*2x)+(4x*-2)+(1*2x)+(1*-2)>=(8x*x)+(8x*5)#

#8x^2-8x+2x-2>=8x^2+40x#

By rearranging:
#-46x-2>=0#

#-46x>=2#

#46x<=-2#

#x<=-2/46=-1/23#

#x<=-1/23#