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Answer 1 · 2017-12-04T21:01:51

Df=#[-1;oo>#
Rgf=#<-oo;0]#

#-sqrt(2x+2)#

the domain of the root square is

#(2x+2)>=0#

#2x+2>=0#

#2(x+1)>=0#

#x+1>=0#

#x>=-1#

then the domain is #[-1;oo>#

the range is

#-1<=x < oo#

for 2

#-2<=2x < oo#

plus 2

#-2+2<=2x+2 < oo#

#0<=2x+2< oo#

root square

#0<=sqrt(2x+2)< oo#

for -1

#0>=-sqrt(2x+2)> -oo#

then the range is

#<-oo;0]#