Question

Question #41629

Answer 1

The scope of this problem is beyond molarity calculations, I've included them in the ICE table below. Although to effectively solve these problems you must be meticulous with them: if you make a trivial mistake here you get the wrong answer to a complex problem.

`H_2(g) + I_2(g) rightleftharpoons 2HI(g)`

`2x = 0.188M => x approx 0.0942M`

Now,

`K_c = ([HI]^2)/([H_2][I_2]) = (0.188^2)/(0.0078^2) approx 581`

is the equilibrium constant under these conditions.