Question

Question #3d50a

Answer 1

Chemical reaction:`2NO_(g)+O_2rArr2NO_2(g)`
As we can see: for the reaction of 1 mole oxygen requires 2 moles of NO
The initial concentration of NO`rarr`0.03`(mol)/(dm^3)`
and `O_2rArr0.04(mol)/(dm^3)`
In this reaction NO is limiting reactant because 0.04`(mol)/(dm^3)` oxygen reacts with 0.08`(mol)/(dm^3)` of NO
But The initial concentration of NO`rarr`0.03`(mol)/(dm^3)`
The concentration of products formed depends on that of NO

when 0.01`(mol)/(dm^3)` reacted the concentration of NO reacted is 0.02`(mol)/(dm^3)`{according to stotiometry}to give 0.02`(mol)/(dm^3)` product NO2

`NO_2 formed rarr0.02(mol)/(dm^3)`
NO left`rarr`0.01`(mol)/(dm^3)`
O2 left`rarr`0.03-0.01=0.02`(mol)/(dm^3)`