Question

Question #2f9e0

Answer 1

Volume of Mixture`rArr`16.8L

Explanation:

2 gms of He`rArr(2)/(4)=` 0.5mol
7 gms of `N_2(g)rArr(7)/(28)=` 0.25mol

Total moles of the Mixture`rArr`0.5+0.25`=`0.75mol

An ideal gas at STP has 22.4 Litres per 1 mol of the gas.

0.75 mol of mixture gas occupies 22.4`xx`0.75L`rArr` 16.8Litres