How do you solve this system of equations: #4x + 6y = 40 and 12x + 7y = 54#?

Question

795 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-06T03:00:03

y=6, x=1

#4x+6y=40#
#12x+7y=54#

#4x+6y=40#
#x=\frac{-3y+20}{2}#

# \frac{-3y+20}{2}+7y=54#

#-11y+120=54#

#-11y=-66#

#y=-66/-11#
#y=6#

#x=\frac{-3*6+20}{2}\quad \Rightarrow \quad x=1#