How do you solve 4a ^ { 2} + 4a < 3( a + 1)?

1 Answer

Use the distributive property, make it equal to zero and find a with the quadratic formula.

Explanation:

For the purpose of this explanation;
Let a be x
Put all x's on one side.
4x^2+4x-3(x+1)<0
Distribute
4x^2+4x-3x-3
Combine like terms
4x^2+x-3
Use x=(-b(+-)sqrt(b^2-4ac))/(2a)
And get x>3/4 and x< -1