How to find the minimum of n for which ((2^n)-1)lna/(2^(n-1)*n) < 0.01*lna ?

1 Answer
Dec 6, 2017

n ge 200

Explanation:

((2^n-1)lna)/(2^(n-1)*n) < 0.01*lna

Assuming lna > 1 we have

2^n-1 < 0.01/2 2^n n or

2^n(1-n/200 ) < 1 rArr n ge 200