Question

Question #62f84

Answer 1

weight of 7.25mol of `C_12H_24O_6=rArr1914g`

7.25 mol of `C_12H_24O_6` contains `7.25N_a` number of molecules.

Explanation:

Molecular weight of `C_12H_24O_6rArr264(g)/(mol)`.

weight of 7.25mol of `C_12H_24O_6=264(g)/(cancel(mol))xx7.25cancel(mol)`
`rArr1914g`

1 mole of a substance contains Avogadro number{`N_a`}of molecules.

7.25 mol of `C_12H_24O_6` contains `7.25N_a` number of molecules.