Question

How do you simplify `\frac { 2x ^ { 3} y ^ { - 5} z ^ { 4} } { 8x ^ { 4} y ^ { - 2} }`?

Answer 1

See below.

Explanation:

`(2x^3y^(-5)z^4)/(8x^4y^(-2))=(2x^3z^4)/(8x^4y^(-2)y^5)=(2x^3z^4)/(8x^4y^3)=(2z^4)/(8xy^3)=(z^4)/(4xy^3)`