How do you solve #3( x + 2) \geq - 6#?

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Answer 1 · 2017-12-07T12:56:05

See a solution process below:

First, divide each side of the inequality by #color(red)(3)# to eliminate the parenthesis while keeping the inequality balanced:

#(3(x + 2))/color(red)(3) >= -6/color(red)(3)#

#(color(red)(cancel(color(black)(3)))(x + 2))/cancel(color(red)(3)) >= -2#

#x + 2 >= -2#

Now, subtract #color(red)(2)# from each side of the inequality to solve for #x# while keeping the inequality balanced:

#x + 2 - color(red)(2) >= -2 - color(red)(2)#

#x + 0 >= -4#

#x >= -4#