How do you solve #x^ { 2} - 24+ 5x = 0#?

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Answer 1 · 2017-12-09T00:28:11

#x=8" "# or #" "x = -5#

Given:

#x^2-24+5x = 0#

Let's rewrite it in standard form:

#x^2+5x-24=0#

Note that #24 = 8 * 3# and #8 - 3 = 5#

So we find:

#0 = x^2+5x-24 = (x-8)(x+5)#

Hence:

#x = 8" "# or #" "x = -5#