How do you solve #4x + 3x - 6x + x + 4x = 12#?

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Answer 1 · 2017-12-09T12:10:12

See a solution process below:

First, combine the like terms on the left side of the equation:

#4x + 3x - 6x + x + 4x = 12#

#4x + 3x - 6x + 1x + 4x = 12#

#(4 + 3 - 6 + 1 + 4)x = 12#

#6x = 12#

Now, divide each side of the equation by #color(red)(6)# to solve for #x# while keeping the equation balanced:

#(6x)/color(red)(6) = 12/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) = 2#

#x = 2#