Question

Question #f4a59

Answer 1

Ammonia is generally formed by the following reaction,

`N_2(g) + 3H_2(g) to 2NH_3(g)`

Now, let's do some stoichiometry,

`2.42g * ("mol"H_2)/(2.00g) * (2NH_3)/(3H_2) * (6.02*10^23"molecules")/("mol") approx 2.43*10^23"molecules"`

of `NH_3` are formed, assuming `H_2` is the limiting reactant.