Question

How do you evaluate `\frac { 8b ^ { 2} + 80b } { 8b ^ { 2} - 8b } \div \frac { 3b - 24} { b ^ { 2} - 9b + 8}`?

Answer 1

`(b+10)/3`

Explanation:

`(8b^2+80b)/(8b^2−8b)÷(3b−24)/(b^2−9b+8)`

`(8b(b+10))/(8b(b−1))÷(3(b−8))/((b−8)(b-1))`

`(b+10)/(b−1)*(b-1)/3`

`(b+10)/1*1/3`

`(b+10)/3`