How do you solve this system of equations: -x + 2y = 10 and 3x + 4y = - 10?

1 Answer
Dec 10, 2017

the solutions are x=-6,y=2

Explanation:

given system of equations
-x+2y=10->(1)
3x+4y=-10->(2)
multiplying (1) by 3 we get
-3x+6y=30->(3)
(3)+(4)
-3x+6y-30+3x+4y+10=0rArr10y-20=0
rArr10y=20rArry=2
put y=2 in (3) we get
-3x+12=30rArr-3x=18rArrx=-6
:.x=-6,y=2