Evaluate the integral. ?

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1 Answer
Dec 10, 2017

-73/6

Explanation:

int_0^1 (u+3)(u-4)du
=int_0^1 (u^2-4u+3u-12)du
=int_0^1 (u^2-u-12)du

Use int x^n dx=x^(n+1)/(n+1)+C

=[u^3/3-u^2/2-12u]_0^1

Using part 2 of fundamental theorem calculus:
int_a^b f'(x) dx=f(b)-f(a)

=(1^3/3-1^2/2-12*1)-(0^3/3-0^2/2-12*0)
=1/3-1/2-12
=-73/6