How do you solve #\frac { 12} { 7} r - 1= \frac { 5} { 7} r#?

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Answer 1 · 2017-12-10T10:17:00

#r=1#

Start:
#(12)/7r-1=5/7r#

Subtract #5/7r# from both sides to get all #r# terms on the same side:

#(12)/7r-5/7r-1=0\rightarrow 7/7r-1=0\rightarrow r-1=0#

Add 1 to both sides to isolate #r#:

#r=1#

Answer 2 · 2017-12-10T10:18:54

# r = 1 #

To solve this we must rearnage:

#(12r)/7 - 1 = (5r)/7#

Minusing #(5r)/7# from both sides:

#(12r)/7 - (5r)/7 - 1 = 0 #

#= (7r)/7 -1 = 0 #

The #7# cancels:

#= r - 1 = 0#

Plus 1 to each side:

#r = 1 #