Question

Question #6018c

Answer 1

`356 - 293 = 63` , or "6 tens and 3 ones".

`49 xx 10 + 82 xx 1 - (12 xx 10 + 96 xx 1) - (6 xx 10 + 3 xx 1) = 293`

Explanation:

Using the place descriptions, the equation is:

`49 xx 10 + 82 xx 1 - (12 xx 10 + 96 xx 1) = 293`

`490 + 82 - (120 + 96) = 293`
`572 - 216 = 293`
`356 = 293` SO the "missing factor" on the other side must be

`356 - 293 = 63` , or "6 tens and 3 ones".

`49 xx 10 + 82 xx 1 - (12 xx 10 + 96 xx 1) - (6 xx 10 + 3 xx 1) = 293`

Answer 2

The value of `x` is `63`
You can express this amount as "6 tens 3 ones."

Explanation:

I think the question has a typo where the `x`'s didn't show up.

I think the question should be:
If 49 tens 82 ones - 12 tens 96 ones = `x` + 293, then find the value of `x`

This question implies that "293" is too small, and it wants to know how much you'd need to add to make the answer correct.

Here is a good way to solve this problem.

1) For your own convenience, turn the bills into a sum of money.

49 tens  = $490
82 ones = $   82
......................................
Total . . . . . $572

12 tens  = $120
96 ones = $   96
.....................................
Total. . . . . .$216

Now you can write the question like this:
[49 tens 82 ones] `-` [12 tens 96 ones] `=` `x` + 293
[ . . . . . 572 . . . . . ] `-` [ . . . . . 216 . . . . . ] `=` `x` + 293

`572 - 216 = x + 293`
Solve for `x`

1) Combine like terms by doing the subtraction
`356 = x + 293`

2) Subtract 293 from both sides to isolate `x`
`63 = x larr` answer

Answer:
The value of `x` is `63`

Check:
`572 - 216` . . `=` . . . `63 + 293?`
. . . . `356` . . . . .`=` . . . . .`356`
`Check!`