How do you solve #10x - 35= 2( 3x + 5) - 3#?

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Answer 1 · 2017-12-12T07:38:02

Expand brackets
#10x-35=6x+10-3#
Transfer #6x " and" -35#
#10x-6x=35+7#
#4x=42#
#x=42/4#
OR,
#x=10 2/4#
OR,
#x=10.5#